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Sagot :
The factoring the equation (a + 1)² - 4b² we get (a+1+2b)(a+1-2b).
What is the factoring function of (a + 1)² - 4 b²?
Given: (a + 1)² - 4b²
Apply Perfect Square Formula, and we get
(a + b)² = a² + 2 a b + b²
(a + 1)² = a² + 2a1+1²
= a² + 2a1 + 1² - 4 b²
simplifying the equation, we get
a² + 2a1 + 1² = a² + 2a + 1
= a² + 2a + 1 - 4b²
Factor, a² + 2a + 1 = (a + 1)²
= (a + 1)² - 4 b²
Simplify 4 b² = (2 b)²
= (a + 1)² - (2b)²
Apply the Difference of Two Squares Formula, and we get
x² - y² = (x + y)(x - y)
(a + 1)² - (2b)² = ((a + 1) + 2b)((a + 1) - 2 b)
simplifying the equation, we get
= ((a + 1) + 2b)(a + 1) - 2 b)
= (a + 1 + 2b)(a + 1 - 2b)
Therefore, the correct answer is (a+1+2b)(a+1-2b).
To learn more about factoring refer to:
https://brainly.com/question/25829061
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