How many kilojoules of energy must be added to 69. 0 grams of water to change the temperature from 33. 0oc to 95. 0oc? (ch2o = 4. 184 j/g oc, 1 kj = 1000 j)

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04-08-2022
Physics

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How many kilojoules of energy must be added to 69. 0 grams of water to change the temperature from 33. 0oc to 95. 0oc? (ch2o = 4. 184 j/g oc, 1 kj = 1000 j)

Sagot :

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-08-18T07:50:42-04:00

17.90 KJ of energy must be added to 69. 0 grams of water to change the temperature from 33°C to 95°C

Specific heat, the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.

Heat added = H = mc(ΔT )

where,

H = heat

m = mass of water = 69 g

c = specific heat of water = 4.184 J/g/°C

ΔT = change in temperature

H = 69 * 4.184 * ( 95 - 33 )

H = 17899.152 J

= 17.90 KJ

To learn more about specific heat here

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How many kilojoules of energy must be added to 69. 0 grams of water to change the temperature from 33. 0oc to 95. 0oc? (ch2o = 4. 184 j/g oc, 1 kj = 1000 j)

Sagot :

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