Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m will be 54.35 m L.
Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
Molarity = n / V
where
n = number of moles
V = volume of solution in l
Molar mass of [tex]LiNO_{3}[/tex] = M of Li + M of N + 3 * M of O
= 7 + 14 + (3*16)
= 69 g/ mole
since , M = n / V
n = m / molar mass of [tex]LiNO_{3}[/tex]
substituting the value of n
Molarity = (m / molar mass of [tex]LiNO_{3}[/tex] ) / V
V = m / molar mass of [tex]LiNO_{3}[/tex] * Molarity
= 1.5 / 69 * 0.40
= 54.35 mL
To learn more about molarity here
https://brainly.com/question/13386686
#SPJ4
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
