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Sagot :
A proton moving at 7. 0 × 10^4 m/s horizontally enters a region where a magnetic field of 0. 10 t is present, directed vertically downward. The magnitude force acts on the proton due to this field will be 1.12 * [tex]10^{-23}[/tex] N
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.
Force in a magnetic field = q. ( v * B )
where
q = charge of particle = 1.6 * [tex]10^{-27}[/tex] C
v = velocity of particle = 7. 0 × [tex]10^{4}[/tex] m/s
B = 0. 10 T
Force = 1.6 * [tex]10^{-27}[/tex] * 7. 0 × [tex]10^{4}[/tex] * 0. 10
= 1.12 * [tex]10^{-23}[/tex] N
To learn more about magnetic force here
https://brainly.com/question/12959984
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