Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
A proton moving at 7. 0 × 10^4 m/s horizontally enters a region where a magnetic field of 0. 10 t is present, directed vertically downward. The magnitude force acts on the proton due to this field will be 1.12 * [tex]10^{-23}[/tex] N
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.
Force in a magnetic field = q. ( v * B )
where
q = charge of particle = 1.6 * [tex]10^{-27}[/tex] C
v = velocity of particle = 7. 0 × [tex]10^{4}[/tex] m/s
B = 0. 10 T
Force = 1.6 * [tex]10^{-27}[/tex] * 7. 0 × [tex]10^{4}[/tex] * 0. 10
= 1.12 * [tex]10^{-23}[/tex] N
To learn more about magnetic force here
https://brainly.com/question/12959984
#SPJ4
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
