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Sagot :
There will be 5.625 atm pressure of the gas at 250 K when a gas at constant volume has a pressure of 4. 50 atm at 200 K
According to gas law at constant volume the pressure of a given gas is directly proportional to the kelvin temperature .
[tex]P_{1} =T_{1}[/tex] (i)
[tex]P_{2} = T_{2}[/tex] (ii)
Where P and T is the pressure and temperature
Divide equation ( i ) by equation ( ii ) we get
[tex]P_{1}/P_{2}[/tex] = [tex]T_{1}/T_{2}[/tex]
Now putting the value of all given data in above final equation then we get.
4. 50 atm/[tex]P_{2}[/tex] = 200K/250K
[tex]P_{2}[/tex] = 4. 50 atm × 250K/ 200K = 5.625 atm
To learn more about gas law
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