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Given the following reaction: 2O3---->3O2. DeltaH of reaction=-286kJ/mol
What is the Delta H reaction of the reaction 3O2----->2O3

Sagot :

Lanuel

The enthalpy of reaction (ΔH) of the above chemical reaction is equal to -143 kJ/mol.

What is a chemical reaction?

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

What is a balanced equation?

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

Next, we would write the properly balanced chemical equation for this chemical reaction:

                                    3/2O₂ -----> 2/2O₃

Therefore, the enthalpy of reaction (ΔH) of the above chemical reaction is half the enthalpy of reaction (ΔH) of the initial chemical reaction:

Enthalpy of reaction (ΔH) = ½ × -286 kJ/mol

Enthalpy of reaction (ΔH) = -143 kJ/mol.

Read more on enthalpy here: https://brainly.com/question/12993630

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