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Sagot :
1.35 Litres of water need to be added to 750 ml of a 2.8 m hcl solution to make a 1.0 m solution.
Use the following relation:
M1V1=M2V2
Where M is molarity, V is volume and 1 is initial and 2 is the final conditions. Solving for V(2)
M1=2.8 M,V1=750 mL;M2=1.0 M
(2.8 M)×(750 mL)=(1.0 M)×V2
V2=(2.8 M)×(750 mL)(1.0 M) = 2100 mL = 2.1 L
Therefore, Volume of water to be added =2.1 L−0.75 L=1.35 L
Learn more about the Molarity with the help of the given link:
https://brainly.com/question/19517011
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