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How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?

Sagot :

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

What is Molarity?

  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.

Calculation of Required amount of AgCl

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

Learn more about Molarity here:
https://brainly.com/question/8732513

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