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if cos 0= -3/5 in quadrant ii, what is sin 0

Sagot :

The value of sin 0 in quadrant 2 is 4/5

How to determine the identity

Given that cos 0 = -3/5

We have;

  • adjacent = -3
  • hypotenuse = 5

Let's find the opposite side, using Pythagorean theorem

5^2 = x^2 + (-3)^2

25 = x^2 + 9

collect like terms

x^2 = 25 - 9

x^2 = 16

x = √ 16

x = 4

We have that

sin 0 = opposite/hypotenuse

sin 0 = 4/5

It is important to note that the trigonometric identity 'sine' is positive in quadrant 2

sin 0 = 4/5

Hence, the value of sin 0 in quadrant 2 is 4/5

Learn more about quadrant here:

https://brainly.com/question/863849

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