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Answered

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Katy has a bag of yellow and red balls. There are a total of 30 balls in the bag. The probability of drawing a yellow ball is 1/6. How many red balls should be removed from the bag in order to increase the probability to 1/3?

The answer choices are:
a)5
b)9
c)10
d)12
e)15

Sagot :

The answer is e)15 Because : to find out the possibility of drawin yellow balls we should divide the number of yellow balls to total balls,
Let y be the number of yellow balls: 
[tex]\frac { y }{ 30 } [/tex]  and we know that the possibility is equal to [tex]\frac { 1 }{ 6 } [/tex] 
[tex]\frac { y }{ 30 } =\frac { 1 }{ 6 } [/tex] from this equation we find y = 5.
If y=5 the number of red balls is 25. If we decrease red balls 15 total number of balls will be = 15. So since number of yellow  balls did not change :[tex]\frac { 5 }{ 15 } =\frac { 1 }{ 3 } [/tex]
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