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Rewrite 2X = 128 as a logarithmic equation.
Olog,128=2
log2x = 128
log2128 = x
log128x = 2

Rewrite 2X 128 As A Logarithmic Equation Olog1282 Log2x 128 Log2128 X Log128x 2 class=

Sagot :

MrRoyal

The equation 2^x = 128 as a logarithmic equation is log₂(128) = x

How to rewrite the equation as a logarithmic equation?

The equation is given as:

2^x = 128

Take the logarithm of both sides

log(2^x) = log(128)

Rewrite as:

x * log(2) = log(128)

Divide both sides of the equation by log(2)

x = log(128)/log(2)

Apply the change of base rule

x = log₂(128)

Hence, the equation 2^x = 128 as a logarithmic equation is log₂(128) = x

Read more about logarithmic equation at

https://brainly.com/question/25710806

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