Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.


Rewrite 2X = 128 as a logarithmic equation.
Olog,128=2
log2x = 128
log2128 = x
log128x = 2


Rewrite 2X 128 As A Logarithmic Equation Olog1282 Log2x 128 Log2128 X Log128x 2 class=

Sagot :

The equation 2^x = 128 as a logarithmic equation is log₂(128) = x

How to rewrite the equation as a logarithmic equation?

The equation is given as:

2^x = 128

Take the logarithm of both sides

log(2^x) = log(128)

Rewrite as:

x * log(2) = log(128)

Divide both sides of the equation by log(2)

x = log(128)/log(2)

Apply the change of base rule

x = log₂(128)

Hence, the equation 2^x = 128 as a logarithmic equation is log₂(128) = x

Read more about logarithmic equation at

https://brainly.com/question/25710806

#SPJ1

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.