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A pair of ladders whose lengths are 4.2m and 5.6m are leaned onto a wall such that they reach the same height. The base of the longer ladder is 1.96 further away from the base of the wall then the base of the shorter ladder. The distance of the shorter ladder form the wall is:

Sagot :

Answer:

2.52 m

Step-by-step explanation:

let the height be h m.

let the shorter ladder be x m away from the base of wall.

(x+1.96)²+h²=5.6²

x²+h²=4.2²

subtract

(x+1.96)²-x²=5.6²-4.2²

(x+1.96+x)(x+1.96-x)=31.36-17.64

(2x+1.96)(1.96)=13.72

2x+1.96=13.72/1.96=7

2x=7-1.96=5.04

x=5.04/2=2.52