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IF A BASEBALL TEAM CONSISTS OF 18 PLAYERS, HOW MANY POSSIBLE GROUPS
OF 9 MAN TEAMS ARE POSSIBLE?

Sagot :

abidemiokin

The number of ways men can be selected from the team of 18 is 48,620ways

Combination and Permutation

Permutation has to do with arrangement while combination has to do with selection.

If a baseball team consists of 18 players and 9 man are possible in the team, the number of ways the men can be chosen is calculated using the combination formula below;

nCr = n!/(n-r)!r!

Given the following

n =18

r = 9

Substitute

18C9 = 18!/(18-9)!9!
18C9 = 18!/9!9!
18C9 = 48,620

Hence the number of ways men can be selected from the team of 18 is 48,620ways

Learn more on combination here: https://brainly.com/question/3901018

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