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A 30g bullet travelling horizontally at 50 m/s penetrates 10 cm into a wooden block. The average force exerted by the block is: ​

Sagot :

The average force exerted by the block exists at -375 N.

How to find the average force exerted by the block?

Given:

Initial Velocity, u = 50m/s

Displacement, s = 10cm = 0.10m

Mass, m = 0.03Kg

Using the relation,

[tex]$v^{2}-u^{2}=2 a s[/tex]

Substitute the values in the above equation, we get:

[tex]${data-answer}amp;0^{2}-50^{2}=2 \mathrm{a}(0.10) \\[/tex]

[tex]$ \mathrm{a}= -12500 \mathrm{~ms}^{-2}[/tex]

We know that, f = ma

Putting the values, we get:

f = (0.03)(-12500)

f = -375 N

The average force exerted by the block exists at -375 N.

To learn more about average force refer to:

https://brainly.com/question/18652903

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