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Sagot :
The average force exerted by the block exists at -375 N.
How to find the average force exerted by the block?
Given:
Initial Velocity, u = 50m/s
Displacement, s = 10cm = 0.10m
Mass, m = 0.03Kg
Using the relation,
[tex]$v^{2}-u^{2}=2 a s[/tex]
Substitute the values in the above equation, we get:
[tex]${data-answer}amp;0^{2}-50^{2}=2 \mathrm{a}(0.10) \\[/tex]
[tex]$ \mathrm{a}= -12500 \mathrm{~ms}^{-2}[/tex]
We know that, f = ma
Putting the values, we get:
f = (0.03)(-12500)
f = -375 N
The average force exerted by the block exists at -375 N.
To learn more about average force refer to:
https://brainly.com/question/18652903
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