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The length of a certain rectangle is 6 meters more than twice its width. What is the perimeter of the rectangle if the area of the rectangle is 260 square meters?​

Sagot :

rvkacademic

Answer:

Perimeter = 72 meters

Step-by-step explanation:

Let L be the length and W the width of the rectangle

We have the following relationship

L = 2W + 6

Area of the rectangle = LW = (2W+6)W   by substituting for L

Area =

2W² + 6W =260 ==> 2W² + 6W -260 = 0

Dividing both sides by 2 yields

W² + 3W -130 = 0

This is a quadratic equation which can be solved using the formula for the roots of the equation ie the values of W which satisfy the above equation

However in this case it is easier to solve by factorization

W² + 3W -130  

= W² + 13W - 10W - 130
= W(W + 13) -10(W + 13)

= (W+13)(W-10) = 0

This means W is either -13 or W = 10

Since W cannot be negative, we get W = 10 and

L = 2(10) + 6 = 26

Perimeter of a rectangle is given by

2(L + W) = 2(26 + 10) = 2(36) = 72  Answer

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