Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

2. The sum to infinity of an exponential sequence with a positive common ratio is 25 and the first two terms is 16. find fifth term

Sagot :

Answer:

0

Step-by-step explanation:

hi

hi

haha

and

and

are doing

dog food

0 answer

(scroll to bottom for answer)The equation you want to be using is A(n)+1=(A(n))r because this is a exponential sequence

r represents the ratio, which you said was 25, so basically you said

A(n)

____     = 25

A(n)-1

rthe sum of the first 2 terms are 16, the first two terms being A1 and A2, they need to follow the equation:

A2

__  = 25

A1

lets give them variables to make this a bit easier-

A1 will be x and A2 will be y

x+y=16(1st equation)

y/x=25, 25x=y(2nd equation)

(if you multiply y/x=25 by x you will get that 25x=y, which is where that other equation came from)

going back to x+y=16

subtract y from both sides

x=16-y

use substitution and solve for the second equation

25(16-y)=y

distribute

400-25y=y

add 25y to both sides to get rid of the -25y on the left side while keeping the equation equal

400=26y

divide both sides by 26 and you get 400/26 which simplifies to 200/13

after all that you need to multiply 200/13 by 25, 3 separate times

200                              1875000

___ x 25 x 25 x 25= _________

13                                      13

pull it into a calculator and you get something like

142846.153846

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.