a. altitude = CE
b. bisector = BD
c. exterior angle = ∠ABE
d. median = CF
e. remote interior angles = ∠BCE and ∠CEB
Geometry
From the question, we are to fill in the blanks
In ΔBCE, we have that ∠BCE is a right angle
Thus,
a. altitude = CE
Also, we have that
∠EBD ≅ ∠CBD
Thus, BD is a bisector
b. bisector = BD
The exterior angle of the triangle is ∠ABE
c. exterior angle = ∠ABE
From the given information,
BF ≅ EF
∴ F is the midpoint of BE
NOTE: Median is a line segment joining the vertex of one side of the triangle to the midpoint of its opposite side.
The median of the triangle is CF
d. median = CF
The remote interior angles of the triangle are ∠BCE and ∠CEB
e. remote interior angles = ∠BCE and ∠CEB
Hence,
a. altitude = CE
b. bisector = BD
c. exterior angle = ∠ABE
d. median = CF
e. remote interior angles = ∠BCE and ∠CEB
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