Evelyn0isley
Answered

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What is the center of the ellipse x2+5y2–45=0?
Write your answer in simplified, rationalized form.
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Sagot :

VectorFundament120

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

[tex]\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1[/tex]

Where center is at point (h,k)

From the equation of [tex]\displaystyle{x^2+5y^2-45=0}[/tex]. First, we add 45 both sides:

[tex]\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}[/tex]

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

[tex]\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}[/tex]

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

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