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An airplane is heading due north at 700 kph, and a wind blows at 60 kph in the direction s 45° e. what is the plane’s ground speed?

Sagot :

Lanuel

We can infer and logically deduce that airplane’s ground speed is equal to 658.94 kph.

Given the following data:

  • Airplane speed = 700 kph.
  • Wind speed = 60 kph.
  • Angle = 45° due East.

What is speed?

Speed can be defined as the distance covered by an object per unit of time. Thus, speed can be measured in kilometer per hour (kph).

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

How to calculate the plane’s ground speed?

In order to calculate the airplane’s ground speed, we would apply the law of cosine:

C² = A² + D² - 2(A)(D)cosθ

Substituting the given parameters into the formula, we have;

C² = 700² + 60² - 2(700)(60)cos45

C² = 434,203.03

C = √434,203.03

C = 658.94 kph.

In conclusion, we can infer and logically deduce that airplane’s ground speed is equal to 658.94 kph.

Read more on cosine law here: brainly.com/question/11000638

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