The mother has an O blood type means genetically she has [tex]I^{O} I^{O}[/tex]and the father is homozygous means he has [tex]I^{A} I^{A}[/tex]in this situation the child will have only A blood group and genetically the child will have [tex]I^{A} I^{O}[/tex]. Thus the answer is blood type A.
The blood group type will have two genotypes one homozygous condition that is type [tex]I^{A} I^{A}[/tex] or the heterozygous condition that is [tex]I^{A} I^{O}[/tex] but in both conditions phenotypically the person will have type A blood group.
The same happens with the type B blood group where the homozygous [tex]I^{B} I^{B}[/tex]or the heterozygous [tex]I^{B} I^{O}[/tex] in both genotype conditions phenotypically the person will have a B blood group.
This condition is not applied in the O blood group as it will always express in homozygous condition as if A or B present then will dominate so if a person has blood type O then the person always has [tex]I^{O} I^{O}[/tex] in their genotype.
The condition for having blood group O is the father and mother both should have heterozygous genotype then there will be a possibility the child will have O blood group.
Here, in the question, both parents are homozygous as the mother is expressing blood group O then must have homozygous [tex]I^{O} I^{O}[/tex] and it is already mentioned in the question that the father is also homozygous that is [tex]I^{A} I^{A}[/tex] . The Punnett square is given in the image attached.
Hence, as both parents have homozygous genotype and the father has blood type A which is dominant so children will be heterozygous and have A blood group as A is dominant over O.
learn more about the ABO blood group
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