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Sagot :
Step-by-step explanation:
Use the Factor Theorem,
" if x-a is a factor of f(x), then f(a) =0,
So here, since x-3 is a factor then f(3)=0,
So first step, plug in 3 for x for the serperate equations.
[tex] {3}^{2} + ( p + q)3 - q = 0[/tex]
[tex]2(3) {}^{2} + (p - 1)3 + (p + 2q) = 0[/tex]
Simplify both equations,
[tex]9 + 3p + 2q = 0[/tex]
[tex]15 + 4 p + 2q = 0[/tex]
Isolate the constants,
[tex]3p + 2q = - 9[/tex]
[tex]4p + 2q = - 15[/tex]
We have a system of equations so let eliminate a variable, by subtracting the two equations.
[tex] - p = 6[/tex]
[tex]p = - 6[/tex]
Plug p back in for any one of the equations to find q.
[tex]3( - 6) + 2q = - 9[/tex]
[tex] - 18 + 2q = - 9[/tex]
[tex]2q = 4.5[/tex]
So p is -6
q is 4.5
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