Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
1. The empirical formula of the compound is Ti₂O₃
2. The correct answer to the question is: smallest whole-number ratio of the atoms (Option C)
3. The correct answer to the question is: orange-brown (Option A)
4. The empirical formula of the compound is KClO₂
5. The empirical formula of the compound is P₂O₅
1. How to determine the empirical formula
- Ti = 66.6 g
- O = 33.4 g
- Empirical formula =?
Divide by their molar mass
Ti = 66.6 / 48 = 1.3875
O = 33.4 / 16 = 2.0875
Divide by the smallest
Ti = 1.3875 / 1.3875 = 1
O = 2.0875 / 1.3875 = 3/2
Multiply by 2 to express in whole number
Ti = 1 × 2 = 2
O = 3/2 × 2 = 3
Thus, the empirical formula of the compound is Ti₂O₃
2. What is empirical formula?
This is the simplest formula of a compound which shows the smallest whole number ratio of the atoms present in the compound
With the above definition, we can conclude that the correct answer to the question is: smallest whole-number ratio of the atoms (Option C)
3. What colour is shown when nitric acid is added?
In the tin oxide laboratory activity, the colour of the vapor emitted when nitric acid is added to the tin is: orange-brown
NOTE: This colour is visible when we carryout the practical experiment
Thus, the correct answer to the question is orange-brown (Option A)
4. How to determine the empirical formula
- K = 36.6%
- Cl = 33.2%
- O = 29.9%
- Empirical formula =?
Divide by their molar mass
K = 36.6 / 39 = 0.9385
Cl = 33.2 / 35.5 = 0.907
O = 29.9 / 16 = 1.8688
Divide by the smallest
K = 0.9385 / 0.907 = 1
Cl = 0.907 / 0.907 = 1
O = 1.8688 / 0.907 = 2
Thus, the empirical formula of the compound is KClO₂
5. How to determine the empirical formula
- P = 43.6%
- O = 56.4%
- Empirical formula =?
Divide by their molar mass
P = 43.6 / 31 = 1.406
O = 56.4 / 16 = 3.525
Divide by the smallest
P = 1.406 / 1.406 = 1
O = 3.525 / 1.406 = 5/2
Multiply by 2 to express in whole number
P = 1 × 2 = 2
O = 5/2 × 2 = 5
Thus, the empirical formula of the compound is P₂O₅
Learn more about empirical formula:
https://brainly.com/question/24297883
#SPJ1
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.