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Sagot :
(a) The magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.
(b) The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.
(c) The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.
Velocity of the 1000 kg after the collision
Apply the principle of conservation of linear momentum as follows;
Final velocity in x direction
m₁u₁ + m₂u₂ = m₁v₁x + m₂v₂x
where;
- m₁ is mass of 750 kg car
- u₁ is initial velocity of 750 kg mass
- m₂ is mass of 1000 kg car
- u₂ is initial velocity of 1000 kg mass
- v₁ is final velocity of 750 kg mass
- v₂ is final velocity of 1000 kg mass
750(0) + 1000(13) = 750(4 cos 30) + 1000v₂x
13000 = 2,598.1 + 1000v₂x
10,401.9 = 1000v₂x
v₂x = 10.4 m/s
Final velocity in y direction
m₁u₁ + m₂u₂ = m₁v₁y + m₂v₂y
750(0) + 1000(0) = 750(4 sin 30) + 1000v₂y
0 = 1500 + 1000v₂y
v₂y = -1500/1000
v₂y = -1.5 m/s
Resultant final velocity
v = √(v₂ₓ² + v₂y²)
v = √[(10.4)² + (-1.5)²]
v = 10.5 m/s
Direction of the final velocity of 1000 kg car
tanθ = v₂y/v₂ₓ
tanθ = -1.5/10.4
tanθ = -0.144
θ = arc tan(-0.144)
θ = 8.2 ⁰ north west
Kinetic energy of the cars before the collision
K.Ei = 0.5m₁u₁² + 0.5m₂u₂²
K.Ei = 0.5(750)(0)² + 0.5(1000)(13)²
K.Ei = 84,500 J
Kinetic energy of the cars after the collision
K.Ef = 0.5(750)(4)² + 0.5(1000)(10.5)²
K.Ef = 61,125 J
Ratio of the kinetic energy
K.Ef/K.Ei = 61,125/84,500
K.Ef/K.Ei = 0.72
Thus, the magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.
The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.
The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.
Learn more about kinetic energy here: https://brainly.com/question/25959744
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