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Sagot :
[tex](a) 3b^3*4b^5=(3*4)b^{3+5}=12b^8 \\ \\ (b) \frac{3x^2y^3}{9y^5} = \frac{3x^2y^3}{3y^3*3y^2} ^{/3y^3}= \frac{x^2}{3y^2} [/tex]
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