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A piggy bank contains an equal number of pennies, nickels, dimes, and quarters. If the total amount of money in the piggy bank is $7.79, find the number of each type of coin

Sagot :

$7.79 = p number of pennies worth $.01 each, n number of nickels worth $.05 each, d number of dimes worth $.10 each, and q number of quarters worth $.25 each. p = n = d = q
Algebraically, this is written:
7.79 = .01p + .05n + .10d + .25q
Since there is the same number of each type of coin, the variables are all equal to each other. This means that they can all be referred to as 'x'.
7.79 = .01x + .05x + .10x + .25x = .41x
7.79 = .41x
 .41  = .41
19 = x
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7.79 = .01x + .05x + .10x + .25x =
7.79 = .41x
 .41  = .41
x= 19
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