Can someone help with question 51 please I need to break it down

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01-02-2015
Mathematics

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Can someone help with question 51 please I need to break it down

Sagot :

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konrad509 konrad509 · Answer 1 · 2015-02-01T10:53:21-05:00

konrad509 konrad509

01-02-2015

[tex]\dfrac{2}{3}t-3\leq1|\cdot3\\ 2t-9\leq3\\ 2t\leq12\\ t\leq6\\\\ \dfrac{3}{4}t-2>7|\cdot4\\ 3t-8>28\\ 3t>36\\ t>12\\\\ t\leq6 \vee t>12\\ \boxed{t\in(-\infty,6]\cup(12,\infty)} [/tex]

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