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solve the following quadratic equation (x+3)2+25=0

Sagot :

ValyRemus
[tex]2\cdot(x+3)+25=0[/tex] ⇒ [tex]2x+2\cdot3=0-25[/tex]

[tex]2x+6=-25[/tex] ⇒ [tex]2x=-25-6[/tex] ⇒ [tex]2x=-31[/tex]

[tex]x= \frac{-31}{2} [/tex] ⇒ [tex]\boxed {x=-15,5}[/tex]
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