Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

I have no idea how to use this site yet, so I'm just gonna put my algebra problem here. Thanks for any help!
Graph system of equation:
x-2y=2
3+y=6

Sagot :

apologiabiology
I have a hard times putting graphs so I'll just put the answers and say how to graph with paper
so we notice that if we solve the second equation (3+y=6), we get a value for y and no value for x so just draw a horizonal line at the point 3 on the y axis

then make the second equation into slope inercept form y=mx+b
x-2y=2
2y-x=-2
2y=x+2
y=1/2x+1
just put in values for x and get y values, then plot points and get line
find where the line inercepts/crosses the first line (3+y=6) and that is the solution

OR

so a the solution is when both equations are true so just assume both are true and solve for x and y

x-2y=2
3+y=6

first of all the second equation is easy
3+y=6
subtract 3 from both sides
y=3

so we subsitute 3 for y in first equation
x-2(3)=2
x-6=2
add 6 to both sides
x=8
y=3
the solution is the point (8,3)


Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.