Answered

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9^x=27^(x+2)
how do I do that? I don't get how to do it with different bases

Sagot :

konrad509
[tex]9^x=27^{x+2}\\ 3^{2x}=3^{3(x+2)}\\ 2x=3(x+2)\\ 2x=3x+6\\ 3x-2x=-6\\ x=-6[/tex]
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