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You need to prepare 500 mL of a 0.250 M NaOH solution for a titration. What mass of NaOH is needed to
make this solution. You should also describe in detail what the correct way to prepare a solution is including
the reagent mass, transfer, glassware, mixing process, and ultimate utilization?

Sagot :

Eduard22sly

The mass of NaOH needed to prepare the solution is 5 g

What is molarity?

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of sodium hydroxide, NaOH

We'll begin by calculating the moles of NaOH. This can be obtained as follow:

  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity = 0.25 M
  • Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.25 × 0.5

Mole of NaOH = 0.125 mole

How to determine the mass of sodium hydroxide, NaOH

The mass of NaOH needed can be obtained as follow:

  • Molar mass of NaOH = 40 g/mol
  • Mole of NaOH = 0.125 mole
  • Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.125 × 40

Mass of NaOH = 5 g

Thus, to prepare the solution, measure 5 g of NaOH and place it in a 500 mL volumetric flask and make it up to the mark with water.

Learn more about molarity:

https://brainly.com/question/15370276

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