Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

You need to prepare 500 mL of a 0.250 M NaOH solution for a titration. What mass of NaOH is needed to
make this solution. You should also describe in detail what the correct way to prepare a solution is including
the reagent mass, transfer, glassware, mixing process, and ultimate utilization?

Sagot :

Eduard22sly

The mass of NaOH needed to prepare the solution is 5 g

What is molarity?

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of sodium hydroxide, NaOH

We'll begin by calculating the moles of NaOH. This can be obtained as follow:

  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity = 0.25 M
  • Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.25 × 0.5

Mole of NaOH = 0.125 mole

How to determine the mass of sodium hydroxide, NaOH

The mass of NaOH needed can be obtained as follow:

  • Molar mass of NaOH = 40 g/mol
  • Mole of NaOH = 0.125 mole
  • Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.125 × 40

Mass of NaOH = 5 g

Thus, to prepare the solution, measure 5 g of NaOH and place it in a 500 mL volumetric flask and make it up to the mark with water.

Learn more about molarity:

https://brainly.com/question/15370276

#SPJ1

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.