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A cashier has a total of 136 bills, made up of fives and tens. The total value of the money
is $900. How many ten-dollar bills does the cashier have?

Sagot :

Answer:

The number of ten-dollar bills is 44

Step-by-step explanation:

we can transform this verbal problem into a system of equations:

Consider

F the number of fives  and  T the number of tens.

He has a total of 136 bills

means

F + T = 136

The total value of the money is $900

means

5F + 10T = 900

Now ,we got a system to solve:

F + T = 136

5F + 10T = 900

Let’s proceed by elimination:

F + T = 136

5F + 10T = 900

Then

5F + 5T = 5×136 = 680

5F + 10T = 900                

Then

5F + 5T = 680     (Equation 1)

5F + 10T = 900    (Equation 2)

(2) - (1) ⇒ 5T = 900 - 680 = 220

           ⇒ 5T = 900 - 680 = 220

           ⇒ T = 220/5

           ⇒ T = 44

Since  F = 136 - T then F = 136 - 44 = 92

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