Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Your 3 variables in this equation would be:
x
x+1
x+2
as you need these numbers to be consecutive. Because it is asking for the sum, you need to add these three variables and set them equal to 138:
(x)+(x+1)+(x+2)=138
At this point the parentheses don't matter, so they can be removed:
x+x+1+x+2=138
Combine like terms:
3x+3=138
Subtract the three:
3x=135
Divide 135 by 3:
x=45
Then, plug 45 back into the other two variable equations:
45+1=46
45+2= 47
Your 3 consecutive integers are 45, 46, and 47
x
x+1
x+2
as you need these numbers to be consecutive. Because it is asking for the sum, you need to add these three variables and set them equal to 138:
(x)+(x+1)+(x+2)=138
At this point the parentheses don't matter, so they can be removed:
x+x+1+x+2=138
Combine like terms:
3x+3=138
Subtract the three:
3x=135
Divide 135 by 3:
x=45
Then, plug 45 back into the other two variable equations:
45+1=46
45+2= 47
Your 3 consecutive integers are 45, 46, and 47
[tex]x+x+1+x+2=138\\
3x+3=138\\
3x=135\\
x=45\\
x+1=46\\
x+2=47[/tex]
Those numbers are 45,46,47.
Those numbers are 45,46,47.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.