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Considering a 0.1 m formic acid buffer, what is the concentration of formic acid present in a solution of ph 4.25 if the pk of formic acid is 3.75?

Sagot :

Formic acid has a molarity of 0.024 M in a solution.

The formic acid buffer is at a 0.1 M concentration. Accordingly, 0.1 moles of formic acid and formate will be present in a 1 L batch of the buffer solution.

Assume that n is the conjugate base of formic acid, and that m is the amount of formic acid.

0.1 = m+n

The pH of a buffer solution can be determined using the Henderson-Hasselbalch equation shown below.

pH = pKa + log (Conjugate / Acid)

Putting in the values,

4.25 = 3.75 + log (0.1-m / m)

3.16 = 0.1-m / m  

m = 0.024

Thus the concentration of formic acid in solution = 0.024 / 1 L

                                                                        = 0.024 M

For more information on buffer solution: https://brainly.com/question/602584

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