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Sagot :
[tex]a=b+4\\
c=2b\\
a+b+c=28\\\\
b+4+b+2b=28\\
4b=24\\
b=6\\\\
a=6+4\\
a=10\\\\
c=2\cdot6\\
c=12\\\\
\boxed{a=10,b=6,c=12}
[/tex]
Side a, b and c are 10cm , 6cm , 12cm
Given that;
Side a = 4 + Side b
Side c = 2(Side b)
Perimeter of triangle = 28 cm
Find:
Length of each side
Computation:
Assume;
Side b = q
Side a = 4 + q
Side c = 2q
So,
Perimeter of triangle = 28 cm
q + 4 + q + 2q = 28
4q = 24
q = 6
Side a = 10 cm
Side b = 6 cm
Side c = 12 cm
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