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Help!! ASAP!!! 1. Solve:

6(6-4x) + 16x = 8x + 4

2. Evaluate the following expression
|-3d-6| + |-5-d^2| for d=3

3. Solve the formula for t.
S=5r^2t

5. Which equation’s line is steeper and explain how you know
y=3x+7 or
y=1/2x+9


Sagot :

The solution to the questions are:

  • x = 2 in 6(6-4x) + 16x = 8x + 4
  • |-3d - 6| + |-5 - d^2| = 29 when d = 3
  • The formula for t is t = S/5r^2
  • The equation y = 3x + 7 is steeper than y = 1/2x + 9

How to solve the equation?

The equation is given as:

6(6-4x) + 16x = 8x + 4

Open the brackets in the above equation

36 - 24x + 16x = 8x + 4

Collect the like terms

-24x + 16x - 8x = 4 - 36

Evaluate the like terms

-16x = -32

Divide both sides by -16

x = 2

How to evaluate the expression

The expression is given as:

|-3d - 6| + |-5 - d^2|

And the value of d is

d = 3

Substitute d = 3 in |-3d - 6| + |-5 - d^2|

|-3(3) - 6| + |-5 - 3^2|

Evaluate the exponent and expand the bracket

|-9 - 6| + |-5 - 9|

Evaluate the difference

|-15| + |-14|

Remove the absolute bracket

15 + 14

Evaluate the sum

29

How to solve the formula for t?

The formula is given as:

S=5r^2t

Divide both sides of the equation by 5r^2

t = S/5r^2

How to determine which equation’s line is steeper

The equations are given as:

y = 3x + 7

y = 1/2x + 9

The slopes of the above equations are

Slope 1 = 3

Slope 2 = 1/2

The higher the slope, the steeper the line.

This means that, the equation with the higher slope is steeper

Hence, the equation y = 3x + 7 is steeper than y = 1/2x + 9

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