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Sagot :
The probability of rolling an odd number on the first roll and then a number greater than 4 on the second roll is 1/6.
According to the given question.
A cube is rolled two times.
So, the sample space for rolling a cube is given by
S = {(1, 1), (1, 2), (1, 3),(1, 4), (1, 5),(1, 6), (2,1), (2, 2), (2, 3), (2,4), (2, 5), (2, 6),(3, 1)(3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4),(5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Total number of coutcomes = 36
The possible outcomes for rolling an odd number on the first roll and then a number greater than 4 on the second roll = {(1, 5), (1, 6), (3, 5), (3, 6), (5, 5), (5, 6)}
⇒ Total number of favorable outcomes = 6
Thereofore,
The probability rolling an odd number on the first roll and then a number greater than 4 on the second roll
= 6/36
= 1/6
Hence, the probbaility rolling an odd number on the first roll and then a number greater than 4 on the second roll is 1/6.
Find out more information about probability here:
https://brainly.com/question/11234923
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