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Which expressions are completely factored?


Select each correct answer.



16a5−20a3=4a3(4a2−5)


24a4+18=6(4a4+3)


12a3+8a=4(3a3+2a)


30a6−24a2=3a2(10a4−8)

Sagot :

The only expressions that are correctly factored are;

A) 16a⁵ - 20a³ = 4a³(4a² - 5)

B) 24a⁴ + 18 = 6(4a⁴ + 3)

C) 12a³  + 8a = 4a(3a² + 2)

D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)

How to factorize equations?

1) 16a⁵ - 20a³

To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;

4a³(4a² - 5)

2) 24a⁴ + 18

To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;

6(4a⁴ + 3)

3) 12a³  + 8a

To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;

4a(3a² + 2)

4) 30a⁶ - 24a²

To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;

3a²(10a⁴ - 8)

Read more about factorization of equations at; https://brainly.com/question/723406

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