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Sagot :
The time interval needed for the disk to rev from leave to 25.0 m/s is 0.57 s.
What is the time interval?
- A larger period of time can be split up into multiple shorter, equal-length segments.
- These are referred to as time periods. Consider the scenario where you wished to gauge a car's speed over an hour-long trip. You could break up an hour into ten-minute segments.
- In Hz, frequency is defined as the number of cycles per second. Simply divide 1 by the frequency to determine the time interval for a known frequency (e.g., a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; 500 Hz has a time interval of 1/(500Hz) = 0.002 seconds, etc.).
Given:
vo = 0
v = 25.4 m/s
r = 0.95 m
n = 1.21 rev
A.
r*ω = v
ω = v/r
= 25.4/.95
= 26.74 rad/s
B.
θ = 2πn
= 2π × (1.21)
= 7.6 m
Using equation of motion,
ωf^2 = ωi^2 + 2αθ
(26.74)^2 = 2 × α × (7.6)
α = 715.03/15.2
= 47.04 rad/s^2
C.
Using equation of motion,
θ = ωi*t + 1/2*α*t^2
θ = 0 + 1/2*α*t^2
7.6 = 47.04/2 × t^2
= sqrt(0.323)
= 0.57 s
Therefore the correct answer is 0.57 s
To learn more about time interval, refer to:
https://brainly.com/question/479532
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