Answered

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Review. Refer to Section 39.4 . Prove that the Doppler shift in wavelength of electromagnetic waves is described byλ' = λ √ {1+v/c / 1-v /cwhere λ' is the wavelength measured by an observer moving at speed v away from a source radiating waves of wavelength λ

Sagot :

From Equation

[tex]f_{obsever}=f_{source} \sqrt{\frac{1+v_{a}/C}{1-V_{a}/C } }[/tex]

where the velocity of approach, v, is the negative of the velocity of

mutual recession: $v_a= –v$.

thus, C/λ=C/λ[tex]\sqrt{\frac{1+V/C}{1-V/C} }[/tex] and

           λ'=λ[tex]\sqrt{\frac{1-V/C}{1+V/C} }[/tex]

What effect will the Doppler shift have on the wavelength of electromagnetic radiation?

  • The Doppler effect for electromagnetic waves like light is widely used in astronomy to measure the speed at which stars and galaxies approach or recede from us, resulting in blueshift or redshift.
  • The Doppler effect is a change in the observed frequency of a (electromagnetic) wave caused by the relative motion of the source and observer.
  • The doppler shift results in a shift in wavelength at the wave's origin (the frequency of the source never changes). This causes the observer's frequency to shift.
  • The emission of a wave from a moving source causes the wavelength to be shorter in front and longer behind, as shown in the link below.
  • When a body emitting radiation has a non-zero radial velocity relative to an observer, the wavelength of the emission changes depending on whether the body is moving towards or away from the observer. The Doppler shift refers to the observed change in wavelength or frequency.

To learn more about Doppler shift in wavelength of electromagnetic refer to

https://brainly.com/question/26117248

#SPJ4

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