Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.
What is a limit?
A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:
[tex]\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)[/tex]
In this problem, we have that:
- To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
- To the right of x = 3, that is, for values that are greater than x = 3, f(x) -> 4.
Hence the lateral limits are given as follows:
- [tex]\lim_{x \rightarrow 3^-} f(x) = -3[/tex]
- [tex]\lim_{x \rightarrow 3^+} f(x) = 4[/tex]
Since the lateral limits are different, the limit does not exist.
More can be learned about lateral limits at https://brainly.com/question/26270080
#SPJ1
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.