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Points P, Q, and R are collinear. Point Q is between P and R, PQ = 3a + 11, PR = 18a - 16, and QR = 5a + 3. Find PQ.​

Sagot :

varshamittal029

We find the length of PQ as 20.

We are given that the points P, Q, and R are collinear.

Also,

Q is in between the points P and R

PQ = 3 a + 11

PR = 18 a - 16

QR = 5 a + 3

We have to find PQ.

Now we know that:

PQ + QR = PR

3 a + 11 + 5 a + 3 = 18 a - 16

8 a + 14 = 18 a - 16

18 a - 8 a = 16 + 14

10 a = 30

a = 3

Putting it in PQ to find its value:

PQ = 3 a + 11

PQ = 3 (3) + 11

PQ = 9 + 11

PQ = 20.

Therefore, we find the length of PQ as 20.

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