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3²x+¹ – 10(3^x) + 3 =0

Sagot :

By using properties of exponential expressions and algebra properties for polynomials, the roots of the polynomial-like trascendent equation are x₁ = 1 and x₂ = - 1.

How to solve a polynomial-like trascendent equation

In this problem we have a quadratic-like formula with exponential expressions (3ˣ), which may be solved by understanding properties of exponential expressions and algebra properties for polynomials:

3²ˣ ⁺ ¹ - 10 · 3ˣ + 3 = 0

3 · 3²ˣ  - 10 · 3ˣ + 3 = 0

3 · (3ˣ)² - 10 · 3ˣ + 3 = 0

If u = 3ˣ, then:

3 · u² - 10 · u + 3 = 0

u² - (10 / 3) · u + 1 = 0

(u - 3) · (u - 1 / 3) = 0

Hence, 3ˣ = 3 or 3ˣ = 1 / 3, whose roots are x₁ = 1 and x₂ = - 1.

Remark

The statement is incomplete and poorly formatted. Complete form is shown below:

Please solve for x in the following formula:

3²ˣ ⁺ ¹ - 10 · 3ˣ + 3 = 0

To learn more on exponential functions: https://brainly.com/question/14355665

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