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Sagot :
By using properties of exponential expressions and algebra properties for polynomials, the roots of the polynomial-like trascendent equation are x₁ = 1 and x₂ = - 1.
How to solve a polynomial-like trascendent equation
In this problem we have a quadratic-like formula with exponential expressions (3ˣ), which may be solved by understanding properties of exponential expressions and algebra properties for polynomials:
3²ˣ ⁺ ¹ - 10 · 3ˣ + 3 = 0
3 · 3²ˣ - 10 · 3ˣ + 3 = 0
3 · (3ˣ)² - 10 · 3ˣ + 3 = 0
If u = 3ˣ, then:
3 · u² - 10 · u + 3 = 0
u² - (10 / 3) · u + 1 = 0
(u - 3) · (u - 1 / 3) = 0
Hence, 3ˣ = 3 or 3ˣ = 1 / 3, whose roots are x₁ = 1 and x₂ = - 1.
Remark
The statement is incomplete and poorly formatted. Complete form is shown below:
Please solve for x in the following formula:
3²ˣ ⁺ ¹ - 10 · 3ˣ + 3 = 0
To learn more on exponential functions: https://brainly.com/question/14355665
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