Answered

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If f is a function defined by f(x) = x² - 6x + 5,
Find f(0).
Solve f(x) = 0.
5

Sagot :

nuhulawal20

Given the function, the output value of f(0) is 5 and the value of x when f(x)=0 are 5 and 1.

What is the out and input value of f(0) and f(x) = 0 respectively?

Given the function in the question;

  • f(x) = x² - 6x + 5
  • f(0) = ?
  • f(x)=0, x = ?

To determine the output value of f(0), replace all the occurrence of x with 0 in the function and simplify.

f(x) = x² - 6x + 5

f(0) = (0)² - (0)x + 5

f(0) = 0 - 0 + 5

f(0) = 5

To determine the value of x when f(x) = 0, replace f(x) with 0 in the function and simplify.

f(x) = x² - 6x + 5

0 = x² - 6x + 5

x² - 6x + 5 = 0

Factor x² - 6x + 5 using the AC method.

(x-5)(x-1) = 0

x = 5, x = 1

x = 5, 1

Therefore, the output value of f(0) is 5 and the value of x when f(x)=0 are 5 and 1.

Learn more about composite functions here: https://brainly.com/question/20379727

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