At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
We get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
We are given some equation of the lines and we need to find the gradient of the lines which are perpendicular to them.
For this, we will first find the slope of the lines and then reciprocal it and change their signs to obtain the gradient of the perpendicular lines.
a) y = -3 x + 11
Here we can see that the slope of the line is:
m = -3
So, the gradient of the perpendicular line will be:
m' = 1 / 3
b) - x / 4 + 2 y = 0
2 y = x / 4
y = x / 8
slope = m = 1 / 8
Gradient = m' = - 8
c) y = - 3
Slope = m = 0
Gradient = m' = 0
d) y = 2(x - 1) / 3
y = 2/3 x - 1/3
slope = m = 2/3
Gradient = m' = -3/2.
Therefore, we get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
Learn more about gradients here:
https://brainly.com/question/21727173
#SPJ9
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.