Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
We get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
We are given some equation of the lines and we need to find the gradient of the lines which are perpendicular to them.
For this, we will first find the slope of the lines and then reciprocal it and change their signs to obtain the gradient of the perpendicular lines.
a) y = -3 x + 11
Here we can see that the slope of the line is:
m = -3
So, the gradient of the perpendicular line will be:
m' = 1 / 3
b) - x / 4 + 2 y = 0
2 y = x / 4
y = x / 8
slope = m = 1 / 8
Gradient = m' = - 8
c) y = - 3
Slope = m = 0
Gradient = m' = 0
d) y = 2(x - 1) / 3
y = 2/3 x - 1/3
slope = m = 2/3
Gradient = m' = -3/2.
Therefore, we get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
Learn more about gradients here:
https://brainly.com/question/21727173
#SPJ9
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.