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In the figure below, ABCE is a rectangle. CD = DE. What is the ratio of the area of triangle DEF to the area of triangle CEG to the area of triangle CDH?​

In The Figure Below ABCE Is A Rectangle CD DE What Is The Ratio Of The Area Of Triangle DEF To The Area Of Triangle CEG To The Area Of Triangle CDH class=

Sagot :

The ratio of the areas of the triangles DEF, CEG and CDH is given as follows:

1:2:1.

What is the area of a triangle?

The area of a triangle is given by half the multiplication of it's base by it's height.

For this problem, we have that:

  • Each of the three triangles have height AE.
  • Triangles DEF and CDH have bases of equal length, as DE = CD.
  • Triangle CEG has a base that is twice the other triangles, as CE = CD + DE = 2CD = 2DE.

Thus, triangles DEF and CDH have the same area, while the area of CEG is double the area of the other two triangles.

Hence, the ratio of the areas of the triangles DEF, CEG and CDH is given as follows:

1:2:1.

More can be learned about the area of a triangle at https://brainly.com/question/24721131

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