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The area of a trapezoid is given by the equation A = 1/2 * h(b1 + b2), where h is the height and b1 and b2 are the lengths of the parallel bases.



What is the area of a trapezoid in which the height is 6 cm and the two bases are b1 = 16 and b2 = 10?

(Think: what does 1/2 * 6(16 + 10) simplify to, following the order of operations?)

Sagot :

Answer:

A = 78 cm²

Step-by-step explanation:

substitute h = 6 , b₁ = 6, b₂ = 10 into the formula

A = [tex]\frac{1}{2}[/tex] × 6 × (6 + 10) = 3 × 26 = 78 cm²

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