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Element Z has two isotopes with an average atomic mass of 208.99 amu. If one of the isotopes is 67% Z-208, what is the other isotope?

Sagot :

Eduard22sly

The other isotope, given the data is 33% Z-211

Data obtained from the question

Ffrom the question given above, the following data were obtained:

  • Average atomic mass = 208.99
  • Mass of isotope A = 208 amu
  • Abundance of A = 67%
  • Abundance of B = 100 - 67 = 33%
  • Mass of isotope B = ?

How to determine the other isotope

We can obtain the other isotope by calculating the mass. This can be obtain as illustrated below:

Average atomic mass = [(Mass of A × Abundance of A)/100] + [(Mass of B × Abundance of B)/100]

208.99 = [(208 × 67)/100] + [(Mass of B × 33)/100]

208.99 = 139.36 + (Mass of B × 0.33)

Collect like term

Mass of B × 0.33 = 208.99 - 139.36

Mass of B × 0.33 = 69.63

Divide both sides by 0.33

Mass of B = 69.63 / 0.33

Mass of B = 211

Thus, the other isotope is 33% Z-211

Learn more about isotope:

https://brainly.com/question/28223231

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