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if sides of two similar triangles are in the ratio of 8:10, then areas of these triangles are in the ratio

Sagot :

The area of the two similar triangles are in the ratio 16 : 25.

As given in the question,

Let the similar triangles be ABC , EFG.

Sides of triangles ABC , EFG. are in the ratio are  AB:EF =8:10

As per the theorem,

Area of two similar triangles is equal to square of the ratio of the corresponding sides

Area of ΔABC / Area of ΔEFG = AB² / EF²

                                               = 8² / 10²

                                               = 16 /25

Therefore, the area of the two similar triangles are in the ratio 16 : 25.

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