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distance, speed, and time two cyclists, 90 mi apart, start riding toward each other at the same time. one cycles twice as fast as the other. if they meet 2 h later, at what average speed is each cyclist traveling?

Sagot :

Parrain

Based on the distance between the cyclists and the time they meet, the average speed of each cyclist is:

  • Cyclist A = 30 mph
  • Cyclist B = 60 mph

What speed are the cyclists going?

Assume that Cyclist A is going at x speed. That would meant that Cyclist B is going at 2x speed.

The formula for x is:

2x + (2 x 2x) = 90

6x = 90

x = 90 / 6

= 15 mph

The speed of the first cyclist is therefore:

= 2 x 15

= 30 mph

With Cyclist B going twice as fast, the speed is:

= 30 x 2

= 60 mph

Find out more on solving for average speed at https://brainly.com/question/24739297

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