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point charges of 10.8 nc and 51.9 nc are placed 0.500 m apart. what is the electric field halfway between them? indicate direction by a positive or a negative value. keep in mind that a positive vector is one directed to the right and a negative vector is one directed to the left. your answer should be a positive or a negative number with two decimal places, do not include the unit.

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The electric filed is 2 * 10^-5 N/C.

What is the electric field half way between them?

We know that the electric field is exerted on one charge due to the presence of another charge. Now we are asked to find the electric filed that exists between the charges 10.8 nc and 51.9 nc half way between the charges.

Now;

Ue = Kq1q2/r

K = electric field

q1 and q2 = charges

r = distance separating them

Ue = 9 * 10^9 * 10.8 * 10^-9 * 51.9 * 10^-9/(0.5)/2

Ue = 2 * 10^-5 N/C

Learn more about electric field:https://brainly.com/question/15800304

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